Tuesday, June 25, 2013

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Let us first consider the chances of getting each number at least once. The total space will consist of all possible $12$-element sequences of $1,2,\dots,7$ - there are $7^{12}$ of these. How many of these correspond to the event we are interested in? Well, each such event gives a partition of $1,2,\dots,12$ into $7$ non-empty sets (namely, the set of throws when different numbers came out).

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